y^2+17y+60=0

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Solution for y^2+17y+60=0 equation: 



y^2+17y+60=0

a = 1; b = 17; c = +60;
Δ = b2-4ac
Δ = 172-4·1·60
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-7}{2*1}=\frac{-24}{2}
=-12
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+7}{2*1}=\frac{-10}{2}
=-5
$

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